Optimal. Leaf size=695 \[ \text{result too large to display} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.820226, antiderivative size = 695, normalized size of antiderivative = 1., number of steps used = 30, number of rules used = 10, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4205, 4190, 4183, 2531, 6609, 2282, 6589, 4184, 3717, 2190} \[ \frac{28 i a b x^3 \text{PolyLog}\left (2,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{PolyLog}\left (2,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{168 a b x^{5/2} \text{PolyLog}\left (3,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{PolyLog}\left (3,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{840 i a b x^2 \text{PolyLog}\left (4,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{PolyLog}\left (4,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{3360 a b x^{3/2} \text{PolyLog}\left (5,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{PolyLog}\left (5,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{10080 i a b x \text{PolyLog}\left (6,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{10080 i a b x \text{PolyLog}\left (6,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{20160 a b \sqrt{x} \text{PolyLog}\left (7,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{20160 a b \sqrt{x} \text{PolyLog}\left (7,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}-\frac{20160 i a b \text{PolyLog}\left (8,-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}+\frac{20160 i a b \text{PolyLog}\left (8,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}-\frac{42 i b^2 x^{5/2} \text{PolyLog}\left (2,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{PolyLog}\left (3,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{210 i b^2 x^{3/2} \text{PolyLog}\left (4,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{315 b^2 x \text{PolyLog}\left (5,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{315 i b^2 \sqrt{x} \text{PolyLog}\left (6,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{315 b^2 \text{PolyLog}\left (7,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{2 d^8}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}-\frac{2 i b^2 x^{7/2}}{d} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 4205
Rule 4190
Rule 4183
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rule 4184
Rule 3717
Rule 2190
Rubi steps
\begin{align*} \int x^3 \left (a+b \csc \left (c+d \sqrt{x}\right )\right )^2 \, dx &=2 \operatorname{Subst}\left (\int x^7 (a+b \csc (c+d x))^2 \, dx,x,\sqrt{x}\right )\\ &=2 \operatorname{Subst}\left (\int \left (a^2 x^7+2 a b x^7 \csc (c+d x)+b^2 x^7 \csc ^2(c+d x)\right ) \, dx,x,\sqrt{x}\right )\\ &=\frac{a^2 x^4}{4}+(4 a b) \operatorname{Subst}\left (\int x^7 \csc (c+d x) \, dx,x,\sqrt{x}\right )+\left (2 b^2\right ) \operatorname{Subst}\left (\int x^7 \csc ^2(c+d x) \, dx,x,\sqrt{x}\right )\\ &=\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}-\frac{(28 a b) \operatorname{Subst}\left (\int x^6 \log \left (1-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d}+\frac{(28 a b) \operatorname{Subst}\left (\int x^6 \log \left (1+e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d}+\frac{\left (14 b^2\right ) \operatorname{Subst}\left (\int x^6 \cot (c+d x) \, dx,x,\sqrt{x}\right )}{d}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{(168 i a b) \operatorname{Subst}\left (\int x^5 \text{Li}_2\left (-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^2}+\frac{(168 i a b) \operatorname{Subst}\left (\int x^5 \text{Li}_2\left (e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^2}-\frac{\left (28 i b^2\right ) \operatorname{Subst}\left (\int \frac{e^{2 i (c+d x)} x^6}{1-e^{2 i (c+d x)}} \, dx,x,\sqrt{x}\right )}{d}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{(840 a b) \operatorname{Subst}\left (\int x^4 \text{Li}_3\left (-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^3}-\frac{(840 a b) \operatorname{Subst}\left (\int x^4 \text{Li}_3\left (e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^3}-\frac{\left (84 b^2\right ) \operatorname{Subst}\left (\int x^5 \log \left (1-e^{2 i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^2}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{(3360 i a b) \operatorname{Subst}\left (\int x^3 \text{Li}_4\left (-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^4}-\frac{(3360 i a b) \operatorname{Subst}\left (\int x^3 \text{Li}_4\left (e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^4}+\frac{\left (210 i b^2\right ) \operatorname{Subst}\left (\int x^4 \text{Li}_2\left (e^{2 i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^3}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{Li}_3\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{3360 a b x^{3/2} \text{Li}_5\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{Li}_5\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{(10080 a b) \operatorname{Subst}\left (\int x^2 \text{Li}_5\left (-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^5}+\frac{(10080 a b) \operatorname{Subst}\left (\int x^2 \text{Li}_5\left (e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^5}-\frac{\left (420 b^2\right ) \operatorname{Subst}\left (\int x^3 \text{Li}_3\left (e^{2 i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^4}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{Li}_3\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{210 i b^2 x^{3/2} \text{Li}_4\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{3360 a b x^{3/2} \text{Li}_5\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{Li}_5\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{10080 i a b x \text{Li}_6\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{10080 i a b x \text{Li}_6\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{(20160 i a b) \operatorname{Subst}\left (\int x \text{Li}_6\left (-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^6}+\frac{(20160 i a b) \operatorname{Subst}\left (\int x \text{Li}_6\left (e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^6}-\frac{\left (630 i b^2\right ) \operatorname{Subst}\left (\int x^2 \text{Li}_4\left (e^{2 i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^5}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{Li}_3\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{210 i b^2 x^{3/2} \text{Li}_4\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{3360 a b x^{3/2} \text{Li}_5\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{Li}_5\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{315 b^2 x \text{Li}_5\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^6}+\frac{10080 i a b x \text{Li}_6\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{10080 i a b x \text{Li}_6\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{20160 a b \sqrt{x} \text{Li}_7\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{20160 a b \sqrt{x} \text{Li}_7\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{(20160 a b) \operatorname{Subst}\left (\int \text{Li}_7\left (-e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^7}-\frac{(20160 a b) \operatorname{Subst}\left (\int \text{Li}_7\left (e^{i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^7}+\frac{\left (630 b^2\right ) \operatorname{Subst}\left (\int x \text{Li}_5\left (e^{2 i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^6}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{Li}_3\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{210 i b^2 x^{3/2} \text{Li}_4\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{3360 a b x^{3/2} \text{Li}_5\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{Li}_5\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{315 b^2 x \text{Li}_5\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^6}+\frac{10080 i a b x \text{Li}_6\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{10080 i a b x \text{Li}_6\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{315 i b^2 \sqrt{x} \text{Li}_6\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^7}-\frac{20160 a b \sqrt{x} \text{Li}_7\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{20160 a b \sqrt{x} \text{Li}_7\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}-\frac{(20160 i a b) \operatorname{Subst}\left (\int \frac{\text{Li}_7(-x)}{x} \, dx,x,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}+\frac{(20160 i a b) \operatorname{Subst}\left (\int \frac{\text{Li}_7(x)}{x} \, dx,x,e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}+\frac{\left (315 i b^2\right ) \operatorname{Subst}\left (\int \text{Li}_6\left (e^{2 i (c+d x)}\right ) \, dx,x,\sqrt{x}\right )}{d^7}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{Li}_3\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{210 i b^2 x^{3/2} \text{Li}_4\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{3360 a b x^{3/2} \text{Li}_5\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{Li}_5\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{315 b^2 x \text{Li}_5\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^6}+\frac{10080 i a b x \text{Li}_6\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{10080 i a b x \text{Li}_6\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{315 i b^2 \sqrt{x} \text{Li}_6\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^7}-\frac{20160 a b \sqrt{x} \text{Li}_7\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{20160 a b \sqrt{x} \text{Li}_7\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}-\frac{20160 i a b \text{Li}_8\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}+\frac{20160 i a b \text{Li}_8\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}+\frac{\left (315 b^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_6(x)}{x} \, dx,x,e^{2 i \left (c+d \sqrt{x}\right )}\right )}{2 d^8}\\ &=-\frac{2 i b^2 x^{7/2}}{d}+\frac{a^2 x^4}{4}-\frac{8 a b x^{7/2} \tanh ^{-1}\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d}-\frac{2 b^2 x^{7/2} \cot \left (c+d \sqrt{x}\right )}{d}+\frac{14 b^2 x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^2}+\frac{28 i a b x^3 \text{Li}_2\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{28 i a b x^3 \text{Li}_2\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^2}-\frac{42 i b^2 x^{5/2} \text{Li}_2\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^3}-\frac{168 a b x^{5/2} \text{Li}_3\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{168 a b x^{5/2} \text{Li}_3\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^3}+\frac{105 b^2 x^2 \text{Li}_3\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^4}-\frac{840 i a b x^2 \text{Li}_4\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{840 i a b x^2 \text{Li}_4\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^4}+\frac{210 i b^2 x^{3/2} \text{Li}_4\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^5}+\frac{3360 a b x^{3/2} \text{Li}_5\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{3360 a b x^{3/2} \text{Li}_5\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^5}-\frac{315 b^2 x \text{Li}_5\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^6}+\frac{10080 i a b x \text{Li}_6\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{10080 i a b x \text{Li}_6\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^6}-\frac{315 i b^2 \sqrt{x} \text{Li}_6\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{d^7}-\frac{20160 a b \sqrt{x} \text{Li}_7\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{20160 a b \sqrt{x} \text{Li}_7\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^7}+\frac{315 b^2 \text{Li}_7\left (e^{2 i \left (c+d \sqrt{x}\right )}\right )}{2 d^8}-\frac{20160 i a b \text{Li}_8\left (-e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}+\frac{20160 i a b \text{Li}_8\left (e^{i \left (c+d \sqrt{x}\right )}\right )}{d^8}\\ \end{align*}
Mathematica [A] time = 20.8497, size = 954, normalized size = 1.37 \[ \frac{a^2 \left (a+b \csc \left (c+d \sqrt{x}\right )\right )^2 \sin ^2\left (c+d \sqrt{x}\right ) x^4}{4 \left (b+a \sin \left (c+d \sqrt{x}\right )\right )^2}+\frac{b^2 \csc \left (\frac{c}{2}\right ) \csc \left (\frac{c}{2}+\frac{d \sqrt{x}}{2}\right ) \left (a+b \csc \left (c+d \sqrt{x}\right )\right )^2 \sin ^2\left (c+d \sqrt{x}\right ) \sin \left (\frac{d \sqrt{x}}{2}\right ) x^{7/2}}{d \left (b+a \sin \left (c+d \sqrt{x}\right )\right )^2}+\frac{b^2 \left (a+b \csc \left (c+d \sqrt{x}\right )\right )^2 \sec \left (\frac{c}{2}\right ) \sec \left (\frac{c}{2}+\frac{d \sqrt{x}}{2}\right ) \sin ^2\left (c+d \sqrt{x}\right ) \sin \left (\frac{d \sqrt{x}}{2}\right ) x^{7/2}}{d \left (b+a \sin \left (c+d \sqrt{x}\right )\right )^2}-\frac{i b \left (a+b \csc \left (c+d \sqrt{x}\right )\right )^2 \left (\frac{8 b e^{2 i c} x^{7/2} d^7}{-1+e^{2 i c}}+8 i a x^{7/2} \log \left (1-e^{i \left (c+d \sqrt{x}\right )}\right ) d^7-8 i a x^{7/2} \log \left (1+e^{i \left (c+d \sqrt{x}\right )}\right ) d^7+28 i b x^3 \log \left (1-e^{2 i \left (c+d \sqrt{x}\right )}\right ) d^6-56 a x^3 \text{PolyLog}\left (2,-e^{i \left (c+d \sqrt{x}\right )}\right ) d^6+56 a x^3 \text{PolyLog}\left (2,e^{i \left (c+d \sqrt{x}\right )}\right ) d^6+84 b x^{5/2} \text{PolyLog}\left (2,e^{2 i \left (c+d \sqrt{x}\right )}\right ) d^5-336 i a x^{5/2} \text{PolyLog}\left (3,-e^{i \left (c+d \sqrt{x}\right )}\right ) d^5+336 i a x^{5/2} \text{PolyLog}\left (3,e^{i \left (c+d \sqrt{x}\right )}\right ) d^5+210 i b x^2 \text{PolyLog}\left (3,e^{2 i \left (c+d \sqrt{x}\right )}\right ) d^4+1680 a x^2 \text{PolyLog}\left (4,-e^{i \left (c+d \sqrt{x}\right )}\right ) d^4-1680 a x^2 \text{PolyLog}\left (4,e^{i \left (c+d \sqrt{x}\right )}\right ) d^4-420 b x^{3/2} \text{PolyLog}\left (4,e^{2 i \left (c+d \sqrt{x}\right )}\right ) d^3+6720 i a x^{3/2} \text{PolyLog}\left (5,-e^{i \left (c+d \sqrt{x}\right )}\right ) d^3-6720 i a x^{3/2} \text{PolyLog}\left (5,e^{i \left (c+d \sqrt{x}\right )}\right ) d^3-630 i b x \text{PolyLog}\left (5,e^{2 i \left (c+d \sqrt{x}\right )}\right ) d^2-20160 a x \text{PolyLog}\left (6,-e^{i \left (c+d \sqrt{x}\right )}\right ) d^2+20160 a x \text{PolyLog}\left (6,e^{i \left (c+d \sqrt{x}\right )}\right ) d^2+630 b \sqrt{x} \text{PolyLog}\left (6,e^{2 i \left (c+d \sqrt{x}\right )}\right ) d-40320 i a \sqrt{x} \text{PolyLog}\left (7,-e^{i \left (c+d \sqrt{x}\right )}\right ) d+40320 i a \sqrt{x} \text{PolyLog}\left (7,e^{i \left (c+d \sqrt{x}\right )}\right ) d+315 i b \text{PolyLog}\left (7,e^{2 i \left (c+d \sqrt{x}\right )}\right )+40320 a \text{PolyLog}\left (8,-e^{i \left (c+d \sqrt{x}\right )}\right )-40320 a \text{PolyLog}\left (8,e^{i \left (c+d \sqrt{x}\right )}\right )\right ) \sin ^2\left (c+d \sqrt{x}\right )}{2 d^8 \left (b+a \sin \left (c+d \sqrt{x}\right )\right )^2} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.181, size = 0, normalized size = 0. \begin{align*} \int{x}^{3} \left ( a+b\csc \left ( c+d\sqrt{x} \right ) \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [B] time = 3.53755, size = 8640, normalized size = 12.43 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (b^{2} x^{3} \csc \left (d \sqrt{x} + c\right )^{2} + 2 \, a b x^{3} \csc \left (d \sqrt{x} + c\right ) + a^{2} x^{3}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \csc \left (d \sqrt{x} + c\right ) + a\right )}^{2} x^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]